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March 27, 2017

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Light enters a plate of borosilicate crown glass
at an angle of 40.2 degrees  with respect to the nor-
mal to the air-glass surface. If the index of
refraction of the glass is 1.52, find the angle
made by the refracted beam with the normal.
Answer in units of .

  • physics - ,

    Snell's law says that

    sin 40.2 = 1.52 sin(theta)

    theta is the angle of refraction.

    Solve for it.

    sin(theta) = 0.4246

    theta = 25.1 degrees

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