phsyics
posted by leslie .
Light enters a plate of borosilicate crown glass
at an angle of 40.2 degrees with respect to the nor
mal to the airglass surface. If the index of
refraction of the glass is 1.52, find the angle
made by the refracted beam with the normal.
Answer in units of .

Snell's law says that
sin 40.2 = 1.52 sin(theta)
theta is the angle of refraction.
Solve for it.
sin(theta) = 0.4246
theta = 25.1 degrees