Posted by **Anonymous** on Sunday, February 27, 2011 at 11:06pm.

The volume of an adult's stomach ranges from about 50 mL when empty to 1 L when full.If its volume is 500 mL and its contents have a pH of 2, how many moles of H+ does it contain?

- chem -
**DrBob222**, Monday, February 28, 2011 at 12:25am
pH = -log(H^+).

Solve for (H^+) and the answer is in molarity which is moles/L.

Then moles = M x L = ??

- Chem -
**Joseph**, Tuesday, March 1, 2011 at 5:06pm
You are given pH which is (-log[H^+] ). so first you take 10^-2 to get the Molarity of [H^+], then you convert 500 mL to Liters so divide 500 by 1000. Finally you take Molarity times volume in liters to get moles of H^+.

10^-2 = .01

500/1000 = .5

.01 * .5 = 5*10^-3 = Moles of H^+ ions.

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