Tuesday
September 16, 2014

Homework Help: Math

Posted by Hannah on Sunday, February 27, 2011 at 9:03pm.

Find the critical values of P(x)

p(x)= (28+x)(8-x/4)

the answer was p=244-7x+8x-x^2/4

p=-x^2/4 + x + 244
p'= -x/2 +1 = 0
X=2
My question is, I do not understand how they got -7x + 8x at the beginning. I know (28)(8)=244 but I do not get the rest.

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