Posted by Anonymous on .
Find an equation of the tangent line to the curve at the given point.
y = 7 sec x
P = (π/3, 14)
slope of tangent, m =
We now look for a line passing through P1(x0,y0)=(π/3,14) with a slope of m=14sqrt(3).
The equation to use is:
substitute x0=π/3, y0=14, m=14sqrt(3) and simplify to get equation of tangent.