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December 19, 2014

December 19, 2014

Posted by **Hannah** on Sunday, February 27, 2011 at 8:07pm.

g(x)=(x^3+1)(3x^2-1)

I know that the answer is

15x^4-3x^2+6x but I donot know how to get to this. I was using

g'(x) X h(x) + g(x) X h'(x) and I was using the derivatives 3x^2 and 6x but I guess this is wrong. Please help!! Thank you.

- Math(Urgent) -
**Reiny**, Sunday, February 27, 2011 at 8:18pmg '(x) = 6x(x^3+1) + 3x^2(3x^2-1)

= 6x^4 + 6x + 9x^4 - 3x^2

= 15x^4 - 3x^2 + 6x

- Math(Urgent) -
**Hannah**, Sunday, February 27, 2011 at 8:40pmThank You

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