Physics - Please Help
posted by Em on .
An m = 6.80-kg clay ball is thrown directly against a perpendicular brick wall at a velocity of 22.0 m/s and shatters into three pieces, which all fly backward, as shown in the figure. The wall exerts a force on the ball of 2670 N for 0.110 s. One piece of mass m1 = 2.80 kg travels backward at a velocity of 10.1 m/s and an angle of = 32.0° above the horizontal. A second piece of mass m2 = 1.80 kg travels at a velocity of 8.30 m/s and an angle of 28.0° below the horizontal.
I found the velocity of the third piece to be 48.738 m/s
but i need help finding:
What is the direction of the third piece?
how did u find
From conservation of momentum:
initial momentum of ball= (total momentum of the three balls)+(impulse of the wall)
First, lets find the momentum of the entire system in the x-axis.
Now lets take the total momentum in the system in the y-axis
theta= -2.5181760257216 degrees
In other words the third ball will go at the direction 2.5181760257216 degrees below the horizontal.