Posted by Brian on Sunday, February 27, 2011 at 6:21pm.
Determine where the equivalence point is. Note the volume.
mmoles OH^- added in excess is 5.0 mL x M = ??
total volume = mL to arrive at the equivalence point + 5.0 from the base
mmoles/total mL = M of OH^-
pOH = -log(OH^-)
and pH + pOH = pKw = 14. Solve for pH.
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