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algebra

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Graph the following equation: clculte the slope, x-intercept, and y-intercept, and label the the intercelts on the graph.

problem: Find an equationin slope-intercept form passing through the points (2,5) and ( 7,-3).

(2+5)/(7+ -3) = 7/4
so y = (7/4)x +b
using (-2,5)
5= (7/4)(-2) +b
20= -3.5 +4b
b=?
I just can't see to figure it out

  • algebra - ,

    Equation passing through the points (2,5) and ( 7,-3)

    Slope m = (-3 - 5)/(7 - 2)
    m = -8/5

    y = mx + b
    y = -8/5 x + b

    Using point, (2, 5) to find b
    y = -8/5 x + b
    5 = -8/5(2) + b
    5 = -16/5 + b
    b = 5 + 16/5
    b = 25/5 + 16/5
    b = 41/5

    y = -8/5 x + 41/5
    In the form, y = mx + b
    b = y-intercept
    y-intercept = 41/5

    An x-intercept is a point on the graph where y is zero.

    y = -8/5 x + 41/5
    0 = -8/5 x + 41/5
    -8/5 x = -41/5
    x = -41/5 * -5/8
    x = 41/8

    x-intercept = 41/8

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