algebra
posted by PEG .
Graph the following equation: clculte the slope, xintercept, and yintercept, and label the the intercelts on the graph.
problem: Find an equationin slopeintercept form passing through the points (2,5) and ( 7,3).
(2+5)/(7+ 3) = 7/4
so y = (7/4)x +b
using (2,5)
5= (7/4)(2) +b
20= 3.5 +4b
b=?
I just can't see to figure it out

Equation passing through the points (2,5) and ( 7,3)
Slope m = (3  5)/(7  2)
m = 8/5
y = mx + b
y = 8/5 x + b
Using point, (2, 5) to find b
y = 8/5 x + b
5 = 8/5(2) + b
5 = 16/5 + b
b = 5 + 16/5
b = 25/5 + 16/5
b = 41/5
y = 8/5 x + 41/5
In the form, y = mx + b
b = yintercept
yintercept = 41/5
An xintercept is a point on the graph where y is zero.
y = 8/5 x + 41/5
0 = 8/5 x + 41/5
8/5 x = 41/5
x = 41/5 * 5/8
x = 41/8
xintercept = 41/8