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September 17, 2014

September 17, 2014

Posted by **PEG** on Sunday, February 27, 2011 at 6:06pm.

problem: Find an equationin slope-intercept form passing through the points (2,5) and ( 7,-3).

(2+5)/(7+ -3) = 7/4

so y = (7/4)x +b

using (-2,5)

5= (7/4)(-2) +b

20= -3.5 +4b

b=?

I just can't see to figure it out

- algebra -
**Helper**, Sunday, February 27, 2011 at 7:17pmEquation passing through the points (2,5) and ( 7,-3)

Slope m = (-3 - 5)/(7 - 2)

m = -8/5

y = mx + b

y = -8/5 x + b

Using point, (2, 5) to find b

y = -8/5 x + b

5 = -8/5(2) + b

5 = -16/5 + b

b = 5 + 16/5

b = 25/5 + 16/5

b = 41/5

y = -8/5 x + 41/5

In the form, y = mx + b

b = y-intercept

y-intercept = 41/5

An x-intercept is a point on the graph where y is zero.

y = -8/5 x + 41/5

0 = -8/5 x + 41/5

-8/5 x = -41/5

x = -41/5 * -5/8

x = 41/8

x-intercept = 41/8

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