physics
posted by Taylor on .
A mesquito whistles a note of 300 Hz, and flies towards you at a speed of 30 m/s. The air temprature is 20 degrees celcius. Before doing any calculations, determine wether you will observe a note that is greater, less than, or equal to 300 Hz (I have already determined it will be less) Then, find the frequency (This is what I need help on, I don't know the formula, and google isn's being helpful!)

Goodness. THe pitch will be greater.
You need to review this:
http://hyperphysics.phyastr.gsu.edu/hbase/sound/dopp.html