Posted by Rachael on Sunday, February 27, 2011 at 3:42pm.
............CH3COOH ==> H^+ + CH3COO^-
initial.....0.02M........0.......0
change........-x.........+x......+x
final......0.02-x.........x.......x
Ka = (H^+)(CH3COO^-)/((CH3COOH)
Plug the ICE chart values into the Ka expression, solve for H, then convert to pH.
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