Posted by Jon on Sunday, February 27, 2011 at 12:49pm.
I agree with your answer of 3.88 for part A (but I don't know that you worked it correctly since you didn't show any work). Part B is done this way.
HAc = CH3COOH = acetic acid.
.................HAc ==> H^+ + Ac^-
initial...........0.1M... .0......0
change............-x......+x......+x
final............0.1-x.....x.......x
Ka = (H^+)(Ac^-)/(HAc)
Plug into Ka expession from the ICE chart I constructed above and solve for (H^+), then convert to pH.
Related Questions
Chemistry (Titration Curves) - Which of the following Acid+Base titration ...
Chem - 25.0 mL of 0.100 M acetic acid (Ka= 1.8 x 10^-5) is titrated with 0.100 M...
Chemistry - Calculate the pH at the equivalence point of 25.0 mL of a 0.100 M ...
Chem - What is the pH of the resulting solution if 30.00 mL of 0.100M acetic ...
Chemistry - 25.0 ml of a 0.100 M solution of the weak acid, CH3OOH is titrated ...
Chemistry - I there, this is my lab worksheet, I am having trouble filling it ...
College Chemistry - I need help with this question!! a sample of pure KHP ...
Chemistry help!! - Consider the titration of the weak acid HA with NaOH. At what...
Chemistry - 40.0 ml of an acetic acid of unknown concentration is titrated with ...
college chemistry - Consider the titration of a 50.0 mL sample of a 0.100 M ...
For Further Reading