maths
posted by Beth .
Make k the subject of the following two equations.
1) 8k+2=3(4k+t)
2)7k+11t=59kt

1)
8k+2 = 3(4k+t)
Expand expressions on each side
8k+2 = 12k + 3t
Group terms involving k on the left hand side
8k  12k = 3t  2
4k = 3t  2
Divide both sides by the coefficient of k, do not forget to insert parentheses on the righthand side:
k = (3t2)/4
Simply and beautify
k = (3t2)/4
= (23t)/4
I leave #2 for your exercise, and post your answer for a check if you wish.