Posted by **Beth** on Sunday, February 27, 2011 at 11:33am.

Make k the subject of the following two equations.

1) 8k+2=3(4k+t)

2)7k+11t=5-9kt

- maths -
**MathMate**, Sunday, February 27, 2011 at 11:53am
1)

8k+2 = 3(4k+t)

Expand expressions on each side

8k+2 = 12k + 3t

Group terms involving k on the left hand side

8k - 12k = 3t - 2

-4k = 3t - 2

Divide both sides by the coefficient of k, do not forget to insert parentheses on the right-hand side:

k = (3t-2)/-4

Simply and beautify

k = -(3t-2)/4

= (2-3t)/4

I leave #2 for your exercise, and post your answer for a check if you wish.

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