draw the electronic configurationd for; 1.Iron chloride,2. Aluminium oxide,3. Benzene
Sure! I can help you understand how to draw the electronic configurations for each of the given compounds.
1. Iron Chloride (FeCl2):
To determine the electronic configuration of an atom, we need to know the atomic number of the element. For iron (Fe), the atomic number is 26.
The electronic configuration of iron can be represented as: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶.
Chlorine (Cl) has an atomic number of 17.
To form Iron Chloride, Fe should lose two electrons, and each chlorine atom will gain one electron.
The electronic configuration of Chlorine is 1s² 2s² 2p⁶ 3s² 3p⁵.
So, the electronic configuration for Iron Chloride (FeCl2) will be:
Iron: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶ (lose 2 electrons)
Chlorine: 1s² 2s² 2p⁶ 3s² 3p⁶ 3p⁵ (gain 1 electron)
2. Aluminium Oxide (Al2O3):
Aluminum (Al) has an atomic number of 13.
The electronic configuration of aluminum is: 1s² 2s² 2p⁶ 3s² 3p¹.
Oxygen (O) has an atomic number of 8.
The electronic configuration of oxygen is: 1s² 2s² 2p⁴.
To form Aluminum Oxide, Al should lose three electrons, and each oxygen atom will gain two electrons.
So, the electronic configuration for Aluminium Oxide (Al2O3) will be:
Aluminum: 1s² 2s² 2p⁶ 3s² 3p¹ (lose 3 electrons)
Oxygen: 1s² 2s² 2p⁴ (gain 2 electrons)
3. Benzene (C6H6):
Benzene is an organic compound composed of carbon (C) and hydrogen (H).
Carbon has an atomic number of 6.
The electronic configuration of carbon is: 1s² 2s² 2p².
Hydrogen has an atomic number of 1.
The electronic configuration of hydrogen is: 1s¹.
To form Benzene, six carbon atoms bond together in a ring structure, and each carbon atom is bonded to one hydrogen atom.
So, the electronic configuration for Benzene (C6H6) will be:
Carbon: 1s² 2s² 2p² (six times)
Hydrogen: 1s¹ (six times)
I hope this explanation helps! Let me know if you have any other questions.