Posted by **jeff** on Saturday, February 26, 2011 at 9:45pm.

6.

a)A 1260 kg car accelerates uniformly from rest to 4.65 m/s in 2.6 s.

Find the work done on the car in this time.Answer in units of J.

b)Find the average power delivered by the engine in the first 1.768 s.

Answer in units of W.

c)Find the instantaneous power delivered by the engine at t2 = 1.274s.

Answer in units of W.

- AP Physics -
**Henry**, Tuesday, March 1, 2011 at 12:59am
a. a = (Vf - Vi)/t,

a = (4.65 - 0) / 2.6 = = 1.788m/s^2.

d = 0.5at^2,

d = 0.5 * 1.788 (2.6)^2 = 6.04m.

F = ma = 1260 * 1.788 = 2252.88N.

W = Fd = 2252.88 * 6.04 = 13607J.

b. P = Fd/t=2252.88 * 6.04/1.768=7696.

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