Posted by bianca on Saturday, February 26, 2011 at 9:29pm.
Find an equation in slopeintercept form passing through the points (2,5) and (7,3).
M=(3,5)/(7,2)
M=8/5 IS THE SLOPE
[Y=MX+B]
5=8/5*2+B
5=16/5+B
5+16/5=B
(25+16)/5=B
41/5=B THE Y INTERCEPT
Y=8X/5 +41/5
HOW WOULD I SHOW A GRAPH ON THIS PROBLEM?

ALGEBRA  Reiny, Saturday, February 26, 2011 at 9:38pm
your slope is incorrect
slope = (2+5)/(7+3) = 3/10
so y = (3/10)x + b
using (3,5)
5 = (3/10)(3) + b
50 = 9 + 10b
b = 41/10
y = (3/10)x  41/10

ALGEBRA  Helper, Saturday, February 26, 2011 at 9:49pm
http://www.purplemath.com/modules/graphlin.htm
I'm not sure of your question.
Do you know how to graph an equation?
Is it because there are fractions?
If because of fractions, convert to decimals and estimate as best you can.
Your equation would be,
y = 1.6 x + 8.2
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