Posted by **bianca** on Saturday, February 26, 2011 at 9:29pm.

Find an equation in slope-intercept form passing through the points (2,5) and (7,-3).

M=(-3,-5)/(7,-2)

M=-8/5 IS THE SLOPE

[Y=MX+B]

5=-8/5*2+B

5=-16/5+B

5+16/5=B

(25+16)/5=B

41/5=B THE Y INTERCEPT

Y=-8X/5 +41/5

HOW WOULD I SHOW A GRAPH ON THIS PROBLEM?

- ALGEBRA -
**Reiny**, Saturday, February 26, 2011 at 9:38pm
your slope is incorrect

slope = (-2+5)/(7+3) = 3/10

so y = (3/10)x + b

using (-3,-5)

-5 = (3/10)(-3) + b

-50 = -9 + 10b

b = -41/10

y = (3/10)x - 41/10

- ALGEBRA -
**Helper**, Saturday, February 26, 2011 at 9:49pm
http://www.purplemath.com/modules/graphlin.htm

I'm not sure of your question.

Do you know how to graph an equation?

Is it because there are fractions?

If because of fractions, convert to decimals and estimate as best you can.

Your equation would be,

y = -1.6 x + 8.2

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