Physics
posted by Ryan on .
A cyclist coasts up a 10.3° slope, traveling 17.0 m along the road to the top of the hill. If the cyclist's initial speed is 9.90 m/s, what is the final speed? Ignore friction and air resistance.
Any help would be great.

The increase in potential energy,
M g 17*sin10.3,
is equal to the decrease in kinetic energy,
(1/2)M[Vo^1 Vf^2]
Vo = 9.90 m/s
Solve for final velocity Vf.
The M's cancel.
Vf^2 = Vo^2  2g*10*sin17.3
Solve for Vf 
The person above me has the correct equation but has the values for the final answer mixed up. instead of doing 9.90^22(9.8)(10)sin(17.3), you should be doing 9.90^22(9.8)(17.3)sin(10.3)..hope that helps!!
NOTE: when you get your answer, make sure you take the square root of it to get your final answer. answer should be in m/s.