Posted by **Ryan** on Saturday, February 26, 2011 at 3:51pm.

A cyclist coasts up a 10.3° slope, traveling 17.0 m along the road to the top of the hill. If the cyclist's initial speed is 9.90 m/s, what is the final speed? Ignore friction and air resistance.

Any help would be great.

- Physics -
**wizardofodds**, Saturday, February 26, 2011 at 4:50pm
The increase in potential energy,

M g 17*sin10.3,

is equal to the decrease in kinetic energy,

(1/2)M[Vo^1 -Vf^2]

Vo = 9.90 m/s

Solve for final velocity Vf.

The M's cancel.

Vf^2 = Vo^2 - 2g*10*sin17.3

Solve for Vf

- Physics -
**FastLearner**, Wednesday, June 15, 2011 at 4:57pm
The person above me has the correct equation but has the values for the final answer mixed up. instead of doing 9.90^2-2(9.8)(10)sin(17.3), you should be doing 9.90^2-2(9.8)(17.3)sin(10.3)..hope that helps!!

NOTE: when you get your answer, make sure you take the square root of it to get your final answer. answer should be in m/s.

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