Posted by Hannah on Saturday, February 26, 2011 at 2:57pm.
A manufacturer estimates that the profit P from producing x units of a commodity is P=x^2+40x100 dollars per week. What is the maximium profit he can realize in one week?
I was going to take the derivative of the equation and set it equal to 0 and then plug it back in but it didn't work. The answer is 300 but I do not know how to get this.

Math  MathMate, Saturday, February 26, 2011 at 3:01pm
Your approach actually works, you might have made an inversion in the sign or something.
P(x)=x²+40x100
P'(x)=2x+40=0 => x= 20
P(20)=20²+40*20100=300 QED

Math  Hannah, Saturday, February 26, 2011 at 3:05pm
oh ok I did I got x=20 instead of 20. Thank you!!

Math  Hannah, Saturday, February 26, 2011 at 3:09pm
but I still do not see how you got 300.
20(2)=400 + 40(20)=800  100 = 1100?

Math  Ryan, Saturday, February 26, 2011 at 3:26pm
Vertex formula= b/2a
= 40/2 = 20
P(20)=(20^2)+(40*20)100
P(20)=(400)+(800)100
P(20)=300

Math  Ryan, Saturday, February 26, 2011 at 3:28pm
Messed up my signs alittle bit should read
P(20)=(20^2)+(40*20)100
P(20)=(400)+(800)100
P(20)=300

Math  MathMate, Saturday, February 26, 2011 at 3:32pm
Exactly...
P(20)=(400)+(800)100 =300

Math  Hannah, Saturday, February 26, 2011 at 3:33pm
oh ok so its 400. Thanks I see now
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