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March 28, 2017

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A manufacturer estimates that the profit P from producing x units of a commodity is P=-x^2+40x-100 dollars per week. What is the maximium profit he can realize in one week?

I was going to take the derivative of the equation and set it equal to 0 and then plug it back in but it didn't work. The answer is 300 but I do not know how to get this.

  • Math - ,

    Your approach actually works, you might have made an inversion in the sign or something.

    P(x)=-x²+40x-100
    P'(x)=-2x+40=0 => x= 20
    P(20)=-20²+40*20-100=300 QED

  • Math - ,

    oh ok I did I got x=-20 instead of 20. Thank you!!

  • Math - ,

    but I still do not see how you got 300.

    -20(2)=400 + 40(20)=800 - 100 = 1100?

  • Math - ,

    Vertex formula= -b/2a
    = -40/-2 = 20

    P(-20)=-(-20^2)+(40*-20)-100
    P(-20)=-(400)+(800)-100
    P(-20)=300

  • Math - ,

    Messed up my signs alittle bit should read

    P(20)=-(20^2)+(40*20)-100
    P(20)=-(400)+(800)-100
    P(20)=300

  • Math - ,

    Exactly...
    P(20)=-(400)+(800)-100 =300

  • Math - ,

    oh ok so its -400. Thanks I see now

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