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Math Help

posted by on .

1) 1+cos(3t)/ sin(3t) + sin(3t)/( 1+ cos(3t))= 2csc(3t)

2) sec^2 2u-1/ sec^2 2u= sin^2 2u

3) cosB/1- sinB= secB+ tanB

  • Math Help - ,

    Please type your equations using brackets to show the proper order of operation.

    The way you typed them, none are identities.

    e.g.
    for the last one you probably meant:
    cosB/(1-sinB) = secB + tanB

    then:
    RS = 1/cosB + sinB/cosB
    = = (1-sinB)/cosB * (1+sinB)/(1+sinB)
    = (1 - sin^2 B)/(cosB(1+sinB)
    = cos^2B/(cosB(1+sinB))
    = cosB/(1+sinB)
    = LS

  • Math Help - ,

    1)1+cos(3t)/ sin(3t) + sin(3t)/( 1+ cos(3t))= 2csc(3t)




    2)sec^2 (2u-1)/ sec^2 (2u)= sin^2 (2u)

  • Math Help - ,

    in 1) since all angles are 3t, I will let x = 3t for easier typing

    Again, the way you typed it, it does not work.
    You must have meant
    (1+cosx)/sinx + sinx/(1+cosx) = 2cscx

    LS = ((1+cosx)^2 + sin^2x)/(sinx(1+cosx))
    = (1 + 2cosx + cos^2x + sin^2x)/(sinx(1+cosx))
    = (2+2cosx)/(sinx(1+cosx))
    = 2(1+cosx)/(sinx(1+cosx))
    = 2/sinx
    = 2cscx, but x = 3t
    = 2csc(3t)
    = RS

    2) does not work the way you typed it.

  • Math Help - ,

    (sin^2 è+ cos^2 è)^3 =1

  • Math Help - ,

    (sin^2 è+ cos^2 è)^3 =1

    That is much too easy!!!!

    what is the value of sin^2 è+ cos^2 è ?

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