Friday

March 27, 2015

March 27, 2015

Posted by **ally** on Friday, February 25, 2011 at 8:19pm.

0.72 kg bullet is 1777 J. The acceleration of gravity is 9.81m/s2.Neglecting air resistance, ﬁnd the range of this projectile when it is ﬁred at an angle such that the range equals the maximum height attained.

Answer in units of km.

- physics -
**drwls**, Saturday, February 26, 2011 at 12:07amFirst calculate the initial velocity Vo, using

(M/2)Vo^2 = 1777 J

If the range equals the maximum height,

2(Vo^2/g)sinA*cosA = (1/2)(Vo^2/g)sin^2A

2 cosA = (1/2)sin A

tanA = 4 A = 76.0 degrees

Use that angle in either the range or the max height formula

**Answer this Question**

**Related Questions**

AP Physics - The initial kinetic energy imparted to a 0.72 kg bullet is 1777 J....

Physics - The initial kinetic energy imparted to a 0.1 kg bullet is 1036 J. The ...

Physics - The initial kinetic energy imparted to a 0.1 kg bullet is 1036 J. The ...

physics - A shell is ﬁred from the ground with an initial speed of 1.70...

Physics - An artillery shell is ﬁred at an angle of 32.2◦ above the...

physics - A bullet is ﬁred straight up from a gun with a muzzle velocity ...

Physics - A bullet is ﬁred straight up from a gun with a muzzle velocity ...

Physics - An artillery shell is ﬁred at an angle of 75.7 above the ...

Physics - Two bullets have masses of 2.4 g and 5.2 g, respectively. Each is &#...

Physics - An artillery shell is fired at an angle of 67.4◦ above the ...