Posted by ally on Friday, February 25, 2011 at 6:00pm.
1. Regardless of the time required, the work done equals thwe kinetic energy change.
2. Assuming that the acceleration rate and force are constant, after 1.768 s, the fraction of the final KE will be
(1.768/2.6)^2 = (0.68)^2 = 0.4624
Compute that amount of energy and divide it by 1.728 s for the average power.
3. Instantaneous power = F*V
Use the time to get the instantaneous V. Get F from F = Ma
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