Cn someone factorise. 3a^2-21a-24

First factor out the 3.

3a^2-21a-24 = 3(a^2 -7a -8)

How about
3(a-8)(a+1) ?

3a^2-21a-24=3(a^2-7a-8)=3(a-8)(a+1).you just look at the l.c.m of the numbrs n divide that numbers by dat l.cm e.g 3,21,n 24 l.cm is 3 u jst divide ths number by dat 3 bt nt 4gtng da base wich is b

I dnt undstnd

Come again

Yes, I can help you factorize the expression 3a^2 - 21a - 24.

To factorize the expression, we need to find two binomials that, when multiplied together, give us the original expression.

First, let's look for the common factors. In this case, we can factor out a common factor of 3 from each term:

3a^2 - 21a - 24 = 3(a^2 - 7a - 8)

Now, we need to factorize the trinomial inside the parentheses, a^2 - 7a - 8.

To factorize the trinomial, we need to find two numbers that multiply to -8 (the last term) and add up to -7 (the coefficient of the middle term).

The numbers that satisfy these conditions are -8 and 1. So, we can rewrite the trinomial as:

a^2 - 7a - 8 = (a - 8)(a + 1)

Therefore, the completely factorized expression is:

3a^2 - 21a - 24 = 3(a - 8)(a + 1)