Posted by Amelie on Friday, February 25, 2011 at 3:48am.
Young's modulus = (tensile stress)/(strain)
In this case the strain is
(delta L)/L = 2.89cm/230 cm
and the stress is
sigma = (78*9.8 N)/[(pi/4)*(8^10^-4m)^2] = 764.4 N/5.027*10^-7 m^2)
= 1.52*10^9 N/m^2
So E = 1.21*10^11 N/m^2
= 121 GPa
A spring stiffness for an individual Ti-Ti interatomic pair can be estimated by dividing
(Tensile force)/(area occupied by one molecule)
by (stretch per intermolecular molecule pair).
You will need a characteristic intermolecular distance or diameter for Ti atoms in the solid. Call it d. Get that from the number density of Ti atoms, n.
d = n^(-1/3)
n = [4.51 g/cm^3/(47.9g/mole)]*6.02*10^23 atom/mole = 5.56*10^22 atom/cm^3
n^-1/3 = d = 2.6*10^-8 cm
= 2.6*10^-10 m
spring stiffness = k
= E/d = 1.21*10^11/2.6*10^-10
= 4.6*10^20 N/m
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