PHysics
posted by Arthur .
A 250 kg load is lifted 23 m vertically with an acceleration a = 0.185g by a single cable
Determine the tension of the cable.
=2900N
Determine the net work done on the load.
=?
Determine the work done by the cable on the load.
=66700 J
Determine the work done by gravity on the load.
=?
Determine the final speed of the load assuming it started from rest.
=?

Determine the tension of the cable.
=2900N Closer to 2906, but OK
Determine the net work done on the load.
(2900N  2450)*23 m = 10,350 J
Determine the work done by the cable on the load.
=66700 J OK
Determine the work done by gravity on the load.
2450*23 = 56,350 J
Determine the final speed of the load assuming it started from rest.
Solve (1/2) M V^2 = 10,350 J for V.