Physics 2
posted by Tiffany on .
A 0.564kg basketball is dropped out of a window that is 5.85 m above the ground. The ball is caught by a person whose hands are 1.89 m above the ground. (a) How much work is done on the ball by its weight? What is the gravitational potential energy of the basketball, relative to the ground, when it is (b) released and (c) caught? (d) What is the change (PEf  PE0) in the ball's gravitational potential energy?

(a) Weight*(distance fallen)
= M*g*3.96 m = ___ J
(b) M*g*Ymax = PEo = PEoriginal
(c) M*g*Ymin = PEf = PEfinal
(d) (c)  (b)
It will be a negative number.