Homework Help: Physics 2

Posted by Tiffany on Thursday, February 24, 2011 at 10:44pm.

A 0.564-kg basketball is dropped out of a window that is 5.85 m above the ground. The ball is caught by a person whose hands are 1.89 m above the ground. (a) How much work is done on the ball by its weight? What is the gravitational potential energy of the basketball, relative to the ground, when it is (b) released and (c) caught? (d) What is the change (PEf - PE0) in the ball's gravitational potential energy?

Physics 2 - drwls, Friday, February 25, 2011 at 5:58am
(a) Weight*(distance fallen)
= M*g*3.96 m = ___ J
(b) M*g*Ymax = PEo = PEoriginal
(c) M*g*Ymin = PEf = PEfinal
(d) (c) - (b)
It will be a negative number.

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