Homework Help: Physics

Posted by Lady22 on Thursday, February 24, 2011 at 7:22pm.

A projectile is launched with an initial speed of 40m/s at an angle of 25 degrees above the horizontal. The projectile lands 3 sec. later. Neglect air friction.

What is the projectile's velocity at the highest point of it's trajectory?

What is the straight line distace from where the projectile was launched to where it hits its target? note that the hill may slope up or down from the launch point.

I'm lost, any help would be great;)

Physics - drwls, Thursday, February 24, 2011 at 7:45pm
At the highest point, the vertical component of velocity is zero (because it has stopped rising), and the horizontal component remains the constant value that it was at launch
V = Vx = Vo cos 25 = 36.25 m/s

Distance to landing point =
Vx * 3s = 108.8 m

Answer this Question

Related Questions

Physics - A projectile is fired up into the air at a speed of 164 m/s at an ...
physics - A projectile is launched at an angle of 54.6 degrees above the ...
physics - A projectile is launched at an angle of 58.5 degrees above the ...
physics - The highest barrier that a projectile can clear is 11.5 m, when the ...
physics - The highest barrier that a projectile can clear is 12.7 m, when the ...
physics - The highest barrier that a projectile can clear is 15.8 m, when the ...
Physics - The highest barrier that a projectile can clear is 14.5 m, when the ...
physics - three more questions: 1) A 1.50kg projectile is launched at 18.0m/s ...
Physics- i need to know how to do these problems - Two projectiles are launched ...
physics - A projectile is launched with an initial speed of 70 m/s at an angle ...

For Further Reading

First Name:
School Subject:
Answer: