multiply the two binomial below
(2x-3)(2x+3)
the answer is 4x^2+9
is this correct
Did you forget -6x?
a) 4x^2+9
B) 4x^2-9
c) 4x^2-6x-9
d) 4x^2 -12x +9
So what is your choice?
A is not correct.
Why did you throw out -3 * 2x?
(2x-3)*(2x+3)=2x*(2x-3)+3*(2x-3)
=4x^2-6x+6x+9
=4x^2+9
Sorry mistake:
(2x-3)*(2x+3)=2x*(2x-3)+3*(2x-3)
=4x^2-6x+6x-9
=4x^2-9
B is correct answer
To multiply two binomials, you need to apply the distributive property. In this case, you have (2x-3)(2x+3).
Step 1: Multiply the first terms in each binomial.
(2x)(2x) = 4x^2
Step 2: Multiply the outer terms in each binomial.
(2x)(3) = 6x
Step 3: Multiply the inner terms in each binomial.
(-3)(2x) = -6x
Step 4: Multiply the last terms in each binomial.
(-3)(3) = -9
Step 5: Simplify the equation by combining like terms.
4x^2 + 6x - 6x - 9
The "+6x" and "-6x" terms cancel each other out, leaving us with:
4x^2 - 9
Therefore, the correct answer is 4x^2 - 9, rather than 4x^2 + 9.