Posted by **Ru** on Thursday, February 24, 2011 at 4:16pm.

When a plane flies into the wind, it can travel 3000mi in 6 hr. When it flies with the wind, it can travel the same distance in 5 hr. Find the rate of the plane in still air and the rate of the wind.

- Algebra 1 -
**Helper**, Thursday, February 24, 2011 at 6:07pm
x = Rate without wind

y = Rate of the wind

T = D/R

6 = 3000/(x - y)

6(x - y) = 3000

6x - 6y = 3000

5 = 3000/(x + y)

5(x + y) = 3000

5x + 5y = 3000

Solve simultaneously,

6x - 6y = 3000

5x + 5y = 3000

5 *(6x - 6y = 3000)= 30x - 30y = 15,000

6 *(5x + 5y = 3000)= 30x + 30y = 18,000

30x - 30y = 15,000

30x + 30y = 18,000

60x = 33,000

x = 550 rate of the plane in still air

5x + 5y = 3000

x = 550

5(550) + 5y = 3000

2750 + 5y = 3000

5y = 250

y = 50 rate of the wind

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