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November 28, 2014

November 28, 2014

Posted by **eric** on Thursday, February 24, 2011 at 9:42am.

- physics -
**Damon**, Thursday, February 24, 2011 at 9:53amWell, I am not going to do it for you but will give some thoughts.

Approach it with energy reasoning.

The frisbee had kinetic energy when it hit the roof, (1/2) m v^2

It lost kinetic energy to potential climbing m g (10 sin 35.5)

It lost kinetic energy due to work done against friction

10 * .45 m g cos 35.5

subtract those two losses from initial Ke

That gives you the speed it departs the roof from Ke remaining =(1/2) m Vi^2

Now you have an ordinary projectile problem

departs the roof with vertical speed Vi sin 35.5

0 = Vi sin 35.5 - t 0

solve for t

H = 0 + Vi sin 35.5 t - 4.9 t^2

- physics -
**eric**, Thursday, February 24, 2011 at 9:54amthanks for the help!

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