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October 24, 2014

October 24, 2014

Posted by **Emilie** on Wednesday, February 23, 2011 at 11:07pm.

prospector pulls with a force of 25 lbs, and the other pulls with a force of 50 pounds. If the angle between the

ropes is 30 degrees, then how much force must the donkey use in order to stay put? (The donkey knows the

proper direction in which to apply his force.)

- Linear Algebra -
**Anida**, Sunday, April 20, 2014 at 8:16pmAssuming the forces are acting 12.5 degrees (25/2) out from the head of the donkey in either direction then the forward force would be 55 * cos12.5 + 75 * cos12.5 = 127 N to 3 s.f. so the donkey pulls backwards with 127 N - but this depends entirely on the orientation of the diagram of forces, if there is one

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