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April 18, 2014

April 18, 2014

Posted by **Tim** on Wednesday, February 23, 2011 at 10:28pm.

- math -
**agrin04**, Friday, February 25, 2011 at 11:41amThe change in altitude: da/dt = 3 cm/min

The change in area: dA/dt = 7 cm^2/min

The change in base: db/dt

From the formula of area of triangle:

A = (a x b)/2

66 = (22 x b)/2

b = 6 cm

Differentiate the formula above with respect to time:

dA/dt = (b. da/dt + a. db/dt)/2

7 = ((6x3) + 22db/dt)/2

db/dt = -2/11 cm/min

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