Homework Help: Physics

Posted by Emily Grossman on Wednesday, February 23, 2011 at 9:48pm.

A 65kg trampoline artist jumps vertically upward from the top of a platform with a speed of 5.0m/s. a) How fast is he going as he lands on the trampoline, 3.0m below. b) if the trampoline behaves like a spring with a spring stiffness constant 6.2*10^4N/m, how far does he depress it?

Physics - drwls, Thursday, February 24, 2011 at 2:39am
a) When hitting the trampoline H=3.0 m below, the kinetic energy will have increased
from (1/2)MVo^2 to
(1/2)MV1^2 =
(1/2)MVo^2 + MgH

Solve for V1
V1^2 = Vo^2 + 2gH

b) (1/2)MV1^2 = (1/2)kX^2
Solve for X, the trampoline displacement.
Physics - telly, Tuesday, January 17, 2012 at 9:51pm
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