Posted by heather on Wednesday, February 23, 2011 at 6:28pm.
Assume a constant acceleration rate in the cannon. The average speed while going out is 17.1/0.772 = 22.15 m/s
The exit speed is twice that: 44.3 m/s
Impulse = Force*time = Momentum change
= (Mass)*(exit velocity)
Force = (Mass)(exit velocity)/time
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