a grocery store stocks 3 brands of yogurt.store sells two containers of brand A yogurt for every one container of brand B or brand C yogurt.if the store sells 100 containers of yogurt a day,how much of each brand of yogurt do they sell?
A = 2B = 2C
A + A/2 + A/2 = 100
2A = 100
Calculate it from there.
The grocery stocks yougurt in 2 refridgerators and sells them for 2.20 per container. Overnight one refridgerator malfunctions and ruins 15 containers of yogurt. The leftover yogurt sold for $3.98 each. How many containers did the store have to begin with if they made a profit of $114.74?
Let's solve this step-by-step:
Let's assume the number of containers of brand A yogurt sold per day as x.
As given, the store sells two containers of brand A yogurt for every one container of brand B or brand C yogurt. So, the number of containers of brand B yogurt sold per day would be x/2, and the number of containers of brand C yogurt sold per day would also be x/2.
Since the store sells 100 containers of yogurt per day, we can add up these quantities:
Number of containers of brand A yogurt (x) + Number of containers of brand B yogurt (x/2) + Number of containers of brand C yogurt (x/2) = Total number of containers sold (100)
x + x/2 + x/2 = 100
Combining like terms:
(2x + x + x) / 2 = 100
Simplifying:
4x / 2 = 100
2x = 100
Dividing both sides by 2:
x = 50
Therefore, the store sells 50 containers of brand A yogurt, 25 containers of brand B yogurt, and 25 containers of brand C yogurt every day.
To solve this problem, we can use algebraic equations. Let's assign variables to each brand of yogurt: Let A represent the number of brand A yogurt containers sold, B represent the number of brand B yogurt containers sold, and C represent the number of brand C yogurt containers sold.
From the given information, we know that the store sells two containers of brand A yogurt for every one container of brand B or brand C yogurt. Therefore, the following equations can be established:
A = 2B (equation 1)
A = 2C (equation 2)
We also know that the store sells a total of 100 containers of yogurt per day. So the sum of the containers sold for each brand should equal 100:
A + B + C = 100 (equation 3)
To find the values of A, B, and C, we need to solve this system of equations.
Substituting equation 1 into equation 3, we can replace A with 2B:
2B + B + C = 100
Combining like terms:
3B + C = 100
Substituting equation 2 into the equation above, we replace A with 2C:
3B + 2C = 100
Now we have a system of two equations:
3B + 2C = 100 (equation 4)
3B + C = 100 (equation 5)
To solve for B, we can subtract equation 5 from equation 4:
(3B + 2C) - (3B + C) = 100 - 100
Simplifying:
B = 0
Now, substituting B = 0 into equation 5, we find that C = 100.
Lastly, substituting B = 0 and C = 100 into equation 3, we find that A = 100.
Therefore, the store sells 100 containers of brand A yogurt, 0 containers of brand B yogurt, and 100 containers of brand C yogurt per day.