A 2.32 kg book is dropped from a height of +3.7 m.
a.) What is its acceleration?
b.) What is its weight in newtons?
To find the answers to these questions, we'll need to apply the principles of Newtonian physics. Let's break the problem down step by step.
a.) What is its acceleration?
To find the acceleration, we can use the formula for free fall:
acceleration = (final velocity - initial velocity) / time
In this case, the book is initially at rest and falls from a height, so its initial velocity is 0 m/s. We don't have the time directly, but we can find it using the following formula:
time = sqrt((2 * height) / g)
where "g" is the acceleration due to gravity, which is approximately 9.8 m/s^2 on Earth.
Let's substitute the values into the formula and calculate the time:
time = sqrt((2 * 3.7 m) / 9.8 m/s^2) ≈ sqrt(0.754) ≈ 0.869 s
Now that we have the time, we can calculate the acceleration:
acceleration = (0 m/s - 0 m/s) / 0.869 s = 0 m/s^2
Therefore, the acceleration of the book is 0 m/s^2. This means that the book is not accelerating during free fall. It is moving at a constant velocity.
b.) What is its weight in newtons?
The weight of an object can be calculated using the equation:
weight = mass * gravitational acceleration
The mass of the book is given as 2.32 kg, and the gravitational acceleration is approximately 9.8 m/s^2.
Substituting the values, we get:
weight = 2.32 kg * 9.8 m/s^2 ≈ 22.736 N
Therefore, the weight of the book is approximately 22.736 Newtons.