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February 1, 2015

February 1, 2015

Posted by **Erica** on Tuesday, February 22, 2011 at 7:26pm.

- Calc -
**Helper**, Tuesday, February 22, 2011 at 9:37pm4x - x^2

-(x^2 - 4x)

x^2 - 4x = 0

x^2 - 4x + 4 = 0 + 4

(x - 2)^2 = 4

(x - 2)^2 - 4

-(x - 2)^2 + 4

4 - (x - 2)^2

| = integral sign

| 1/(sqrt(4 - (x - 2)^2) dx

u = ( x - 2)

du = dx

| 1/(sqrt(4 - u^2)) du

= arcsin u/2 + C

= arcsin (x - 2)/2 + C

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