Posted by Melanie on Tuesday, February 22, 2011 at 7:18pm.
solve each system
1) 3x + y = 6
2x + 3y = 13
2) 2x + 5y  6 = 0
2x + y  2 = 0
3) x + 3y = 6
4x  5y = 7

Math  MathMate, Tuesday, February 22, 2011 at 9:55pm
I'll solve the first one, leaving you a chance to practice with the rest.
3x + y = 6 .....(1)
2x + 3y = 13 ....(2)
Multiply (1) by 3 and subtract (2) to eliminate y:
9x + 3y = 18 .....(1a)
2x + 3y = 13 .....(2a)
Subtract:
7x = 5
x=5/7 .....(3)
Substitute (3) in 1
3(5/7) + y = 6
y = 615/7
=27/7 ....(4)
Substitute (3) and (4) in (2) to check:
2(5/7) + 3(27/7)
=(10+81)/7
=13 OK.
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