Posted by **Melanie** on Tuesday, February 22, 2011 at 7:18pm.

solve each system

1) 3x + y = 6

2x + 3y = 13

2) 2x + 5y - 6 = 0

-2x + y - 2 = 0

3) x + 3y = 6

4x - 5y = 7

- Math -
**MathMate**, Tuesday, February 22, 2011 at 9:55pm
I'll solve the first one, leaving you a chance to practice with the rest.

3x + y = 6 .....(1)

2x + 3y = 13 ....(2)

Multiply (1) by 3 and subtract (2) to eliminate y:

9x + 3y = 18 .....(1a)

2x + 3y = 13 .....(2a)

Subtract:

7x = 5

x=5/7 .....(3)

Substitute (3) in 1

3(5/7) + y = 6

y = 6-15/7

=27/7 ....(4)

Substitute (3) and (4) in (2) to check:

2(5/7) + 3(27/7)

=(10+81)/7

=13 OK.

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