Posted by **Lindsey** on Tuesday, February 22, 2011 at 6:03pm.

We are learning how to solve systems using elimination.

2y - 1 = 3x - y / 5

3x - 4 / 8 = y/4

How would I begin to solve this? I'm mostly unsure of how to simplify the fractions. Thanks so much :)

- Algebra II -
**Helper**, Tuesday, February 22, 2011 at 6:35pm
2y - 1 = 3x - y/5

3x - 4/8 = y/4

First, simplify both equations

2y - 1 = 3x - y/5

Multiply both sides by 5

10y - 5 = 15x - y

11y - 15x = 5

3x - 4/8 = y/4

Multiply both sides by 8

24x - 4 = 2y

-2y + 24x = 4

Multiply by 2 (11y - 15x = 5)

Multiply by 11 (-2y + 24x = 4)

22y - 30x = 10

-22y + 264x = 44

Add equations

oy + 234x = 54

234x = 54

x = 54/234 = 3/13

Substitute x = 3/13 in either equation to find y.

Check your answer.

If you are correct, y = 10/13

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