Posted by Lindsey on Tuesday, February 22, 2011 at 6:03pm.
We are learning how to solve systems using elimination.
2y  1 = 3x  y / 5
3x  4 / 8 = y/4
How would I begin to solve this? I'm mostly unsure of how to simplify the fractions. Thanks so much :)

Algebra II  Helper, Tuesday, February 22, 2011 at 6:35pm
2y  1 = 3x  y/5
3x  4/8 = y/4
First, simplify both equations
2y  1 = 3x  y/5
Multiply both sides by 5
10y  5 = 15x  y
11y  15x = 5
3x  4/8 = y/4
Multiply both sides by 8
24x  4 = 2y
2y + 24x = 4
Multiply by 2 (11y  15x = 5)
Multiply by 11 (2y + 24x = 4)
22y  30x = 10
22y + 264x = 44
Add equations
oy + 234x = 54
234x = 54
x = 54/234 = 3/13
Substitute x = 3/13 in either equation to find y.
Check your answer.
If you are correct, y = 10/13
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