Two rectangles are each 5 in. wide. The larger rectangle has an area of 35 sq in . and is 2 in longer than the smaller rectangle. What is the area of the smaller rectangle?
Since the larger rectangle has one side 5" and area = 35".
x * 5 = 35
x = 7
But the smaller rectangle has length of x-2.
5(x-2) = ?
WHAT IS THE ANSWER FOR 3 SIXES SIMPLETS FORM
what is the line segment of 2 7/8?
To find the area of the smaller rectangle, we need to break down the information given to solve the problem step by step.
Let's assume the length of the smaller rectangle is 'x' inches.
Given that the width of both rectangles is 5 inches, the area of the smaller rectangle can be calculated using the formula:
Area = Length × Width
Substituting the values, we have:
Area of smaller rectangle = x × 5 sq in
Now, we know that the larger rectangle is 2 inches longer than the smaller rectangle. So, the length of the larger rectangle would be 'x + 2' inches.
Since we are given that the area of the larger rectangle is 35 sq in, we can set up the equation:
Area of larger rectangle = (x + 2) × 5 sq in = 35 sq in
To solve this equation, we can divide both sides by 5:
(x + 2) = 35 / 5
Simplifying further:
x + 2 = 7
Subtracting 2 from both sides:
x = 7 - 2
x = 5
Therefore, the length of the smaller rectangle is 5 inches. Now we can find its area by multiplying the length and width:
Area of smaller rectangle = 5 × 5 sq in = 25 sq in
Hence, the area of the smaller rectangle is 25 square inches.