Homework Help: Chemistry II

Posted by Tiffany on Tuesday, February 22, 2011 at 5:07pm.

At a certain temperature, Kc = 33 for the reaction:

H2(g) + I2(g) 2HI(g)

Assume that the initial concentrations of both H2 and I2 are 6.00 x 10-3 mol/L. Find the concentration of each reactant and product at equilibrium.

Chemistry II - DrBob222, Tuesday, February 22, 2011 at 10:44pm
You need to insert the arrow to know the difference between products and reactants. You have the equation, set up an ICE chart.
....................H2 + I2 ==> 2HI
...initial........0.006..0.006...0
change..............-x....-x.....2x
equilibrium.....0.006-x...0.006-x...2x

Now substitute into the Kc expression of
Kc = 0.33 = (HI)^2/(H2)(I2)
Solve for x and calculate each of the final concns. Post your work if you get stuck.

Answer this Question

Related Questions

Chemistry - For the reaction: H2(g) + I2(g) 2HI(g) , Kc = 12.3 at some ...
Chemistry - Kc for the reaction of hydrogen and iodine to produce hydrogen ...
CHEMISTRY> HELP QUICK! pls - Calculate the reaction free energy of: H2(g...
Chemistry - The decomposition of HI(g) is represented by the equation: 2HI(g) &...
Chemistry - At a certain temperature, the equilibrium constant, Kc, for this ...
chemistry - For the reaction H2(g) + I2(g) ↔ 2 HI(g), you have the ...
chemistry - For the reaction H2(g) + I2(g) ↔ 2 HI(g), you have the ...
chemistry - For the reaction H2(g) + I2(g) ¡ê 2 HI(g), you have the ...
chemistry - At a certain temperature, the Equilibrium constant, Kc, for this ...
Chemistry - When 0.59 mol I2(g) and 0.59 mol H2(g) are placed into a 1.0-L ...

For Further Reading

First Name:
School Subject:
Answer: