Chemistry II
posted by Tiffany on .
At a certain temperature, Kc = 33 for the reaction:
H2(g) + I2(g) 2HI(g)
Assume that the initial concentrations of both H2 and I2 are 6.00 x 103 mol/L. Find the concentration of each reactant and product at equilibrium.

You need to insert the arrow to know the difference between products and reactants. You have the equation, set up an ICE chart.
....................H2 + I2 ==> 2HI
...initial........0.006..0.006...0
change..............x....x.....2x
equilibrium.....0.006x...0.006x...2x
Now substitute into the Kc expression of
Kc = 0.33 = (HI)^2/(H2)(I2)
Solve for x and calculate each of the final concns. Post your work if you get stuck. 
X=1.97406×10 power of 3 .then what is the reactant and product of equilibrium .can't understand actually .