A hammer falls from a scaffold on a building 50.0m above the ground. Find its speed as it hits the ground.
t= square{2h/g},
t=square {100/9.8}
t=square{10.2}
t=3.19
Speed = distance/time
s=50/3.19
s=15.67
s=15.67*2
SPEED=31.3m/s
31.3 m/s
To find the speed at which the hammer hits the ground, we can use the concept of free fall motion. When an object falls freely under the influence of gravity, its speed can be determined using the equation:
v = sqrt(2gh)
Where:
v is the final velocity (speed) of the hammer
g is the acceleration due to gravity (approximately 9.8 m/s^2)
h is the height from which the hammer falls (50.0 m in this case)
Now, let's substitute the given values into the equation to find the speed of the hammer:
v = sqrt(2 * 9.8 m/s^2 * 50.0 m)
v = sqrt(980 m^2/s^2)
v ≈ 31.3 m/s
Therefore, the hammer hits the ground with a speed of approximately 31.3 meters per second.