Posted by **Me** on Tuesday, February 22, 2011 at 1:44pm.

Consider a square of side length a = 9.7 cm with charged particles at each of the corners. Three of the particles carry +9.3 nC of charge while the fourth particle carries -9.3 nC. In volts, what is the electric potential at the center of the square?

Hint: Choose the potential to be zero for a position very far from the square.

- Physics/ electricity -
**bobpursley**, Tuesday, February 22, 2011 at 2:26pm
Add the voltages from each corner, potential is a scalar, and does not have direction.

V= k(29.3nC)( 2/(.097*.707))

check that.

- Physics/ electricity -
**Me**, Tuesday, February 22, 2011 at 3:36pm
Isn't it just suppose to be 9.3nc instead of 29.3nC?

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