algebra
posted by Joel on .
Select the set of equations that represents the following situation: Mary invested one amount at 7% simple interest, and a second amount at 5% interest, earning $29.80 in one year. If she had switched the amounts, she would have earned $35.00. What were the two amounts?

Invested $X @ 7%.
Invested $Y @ 5%.
Eq1: 0.07X + 0.05Y = $29.80.
Eq2: 0.05X + 0.07Y=35(Amountswitched).
Multiply both Eqs by 100:
7X + 5Y = 2980
5X + 7Y = 3500
Multiply 1st Eq by 5 and 2nd Eq by7:
35X 25Y = 14900
35X + 49Y = 24500
Add the 2 Eqs and get:
24Y = 9600,
Y = $400.
Substitute 400 for Y in Eq2:
0.05X + 0.07*400 = 35,
0.05X + 28 = 35,
0.05X = 35  28 = 7,
X = 7 / 0.05 = $140.