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Algebra

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Cody’s motorboat took 3 hr to make a trip downstream with a 6-mph current. The return trip against the same current took 5 hr. Find the speed of the boat in still water

  • Algebra - ,

    Time= distance*velocity

    3=d*(vb+vs)
    5=d(Vb-vs)

    3/d= vb+Vs
    5/d=Vb-Vs

    add the equations

    3/d + 5/d=2Vb

    5d+3d=30Vb
    solve for Vb

  • Algebra - ,

    speed of boat in still water ---- x mph

    distance going upstream = 5(x-6)
    distance going downstream = 3(x+6)

    Are the distances not equal ?

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