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February 27, 2015

February 27, 2015

Posted by **Joel** on Tuesday, February 22, 2011 at 9:08am.

- Algebra -
**Anonymous**, Tuesday, February 22, 2011 at 9:24amTime= distance*velocity

3=d*(vb+vs)

5=d(Vb-vs)

3/d= vb+Vs

5/d=Vb-Vs

add the equations

3/d + 5/d=2Vb

5d+3d=30Vb

solve for Vb

- Algebra -
**Reiny**, Tuesday, February 22, 2011 at 9:27amspeed of boat in still water ---- x mph

distance going upstream = 5(x-6)

distance going downstream = 3(x+6)

Are the distances not equal ?

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