Posted by **lala** on Tuesday, February 22, 2011 at 7:56am.

Factorize (x+2)^2 + x^2 +6x + 8

- Math -
**Brian**, Tuesday, February 22, 2011 at 8:04am
=x^2+4x+4+x^2+6x+8

=2x^2+10x+12

=2(x^2+5+6)

=(x+2)(x+3)

=x=-3,-2

- Math -
**Reiny**, Tuesday, February 22, 2011 at 8:56am
picking up from Brian's third-last line

= 2(x^2+5+6)

should have been

= 2(x^2+5x+6)

= 2(x+2)(x+3)

This is the fully factored form, there was no equation to "solve"

## Answer This Question

## Related Questions

- mathematics - Key: logx= log base x 1. Prove that: (logx64 +logx4 -logx8)/(...
- Math - Factorize: a^2 -1 + 2b - b^2
- Math - Factorize: 3a(3a-2b)+b^2-c^2
- math - factorize :x2-2X+xy-2y
- math - factorize 1) x^2=5x-6 2) 6x^2-20=-7x 3) 6x^2-7x=-2
- Math IB SL - Factorize: 2x^2-xy-6y^2 ????
- math - Factorize the following: 2x^2 + 3x - 7
- math - Please Factorize it- 4*x^3-4*x
- math - Please Factorize it- 16*x^2+8*x-1
- MATH - Factorize the following : x4-x2-6 HELP!!!!!!

More Related Questions