# Calc

posted by
**Erica** on
.

If n is a positive integer, find the limit as n approaches +∞ of 1/n(sin (π/n) + sin (2π)/n + ... + sin (nπ)/n)

posted by
**Erica** on
.

If n is a positive integer, find the limit as n approaches +∞ of 1/n(sin (π/n) + sin (2π)/n + ... + sin (nπ)/n)