The final grade for a particular course is calculated by dividing total points earned by total points available. There are 120 points available in the first half of the course, and 140 points in the second half of the course. If a student earns 81% in the first half ofthe cours, how many pnts must the student earn in the second half in order to earn an 80% B final grade?
To put this in algebriac equation would be
140+120=260*.80=208
120*97
208*97=111
120-X=81%
X=111
I know this is not a correct algebraic expression could you explain how to write this in correct algebraic expression. Thanks for your help
To create a correct algebraic expression for this problem, let's first define the variables:
Let X represent the number of points the student must earn in the second half of the course.
Now, let's break down the problem step by step:
1. Total points available in the entire course = 120 + 140 = 260 points.
2. A final grade of 80% is equivalent to earning 80% of the total points available, which is 260 * 0.80 = 208 points.
3. The student already earned 81% in the first half of the course, which is 81% of the points available in the first half, or 120 * 0.81 = 97.2 points.
Now, we can set up the equation to find the number of points the student must earn in the second half:
97.2 + X = 208
This equation states that the points earned in the first half (97.2) plus the points to be earned in the second half (X) should add up to the required total points (208) for a final grade of 80%.
From here, you can solve for X by subtracting 97.2 from both sides of the equation:
X = 208 - 97.2
Simplifying,
X = 110.8
Therefore, the student must earn 110.8 points in the second half of the course to achieve an 80% B final grade.