Posted by Katherine on Monday, February 21, 2011 at 9:44pm.
(tan/(1+sec)) + ((1+sec)/tan) = 2csc
(Show all work please.)
- Pre-cal/Trig - Reiny, Monday, February 21, 2011 at 10:27pm
I see tangents and secants on the left side, so I suspect to use the identity
tan^2x + 1 = sec^2x
= tanx(1+secx) + (1+secx)/tanx
= (tan^2x + 1 + 2secx + sec^2x)/(tanx(1+secx))
= (sec^2x + 2secx + sec^2x)/(tanx(1+secx))
= (2sec^2x + 2secx)/(tanx(1+secx))
= 2secx(secx + 1)/(tanx(1+secx))
- Pre-cal/Trig - Delano, Wednesday, November 2, 2011 at 4:44pm
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