Posted by Katherine on Monday, February 21, 2011 at 9:44pm.
(tan/(1+sec)) + ((1+sec)/tan) = 2csc
(Show all work please.)

Precal/Trig  Reiny, Monday, February 21, 2011 at 10:27pm
I see tangents and secants on the left side, so I suspect to use the identity
tan^2x + 1 = sec^2x
LS
= tanx(1+secx) + (1+secx)/tanx
= (tan^2x + 1 + 2secx + sec^2x)/(tanx(1+secx))
= (sec^2x + 2secx + sec^2x)/(tanx(1+secx))
= (2sec^2x + 2secx)/(tanx(1+secx))
= 2secx(secx + 1)/(tanx(1+secx))
= 2secx/tanx
= (2/cosx)÷(sinx/cosx)
= (2/cosx)(cosx/sinx)
= 2/sinx
= 2cscx
= RS
Q.E.D.

Precal/Trig  Delano, Wednesday, November 2, 2011 at 4:44pm
y=2sec(1/3x)
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