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December 18, 2014

December 18, 2014

Posted by **Jocelyne** on Monday, February 21, 2011 at 1:03pm.

- Algebra 1 -
**Helper**, Monday, February 21, 2011 at 4:10pmDo you need to find L2?

If two lines are perpendicular, the slope m of one is the negative reciprocal of the slope of the other,

Slope m1 * m2 = -1

or, slope m2 = -1/m1

Your need to find slope m1 to write the equation of the perpendicular line.

L1 = 3x - y = 2

To find slope m, put the equation in slope-intercept form

y = mx + b, where m = slope and b = y-intercept

3x - y = 2

y = 3x - 2

So, slope m1 = 3

Since, m2 = -1/m1 and m1 = 3,

m2 = -1/3 = slope of L2 (perpendicular line)

L2 through point (-5, -1)

Form of the equation is,

y = mx + b

You found the slope m2 = -1/3

y = -1/3 x + b

To find b, use point (-5, -1) and substitute x and y point values in the equation and solve for b

y = -1/3 x + b

y = -5, x = -1

-1 = -1/3 (-5) + b

-1 = 5/3 + b

b = -1 + -5/3

b = -3/3 + -5/3

b = -8/3

So, L2 is

y = -1/3 x + -8/3

y = -1/3 x - 8/3

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