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April 20, 2014

April 20, 2014

Posted by **Susie** on Monday, February 21, 2011 at 12:58pm.

- calculus -
**MathMate**, Monday, February 21, 2011 at 1:37pmDifferentiate both sides with respect to t:

dy/dt = d(sqrt(1+x^3))/dx * dx/dt

=(3x²/(2sqrt(1+x³)))*dx/dt

So given x=2,y=3 and dy/dt=3 cm/s

substitute in formula above to solve for dx/dt.

I get dx/dt=2.

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