Sunday

December 21, 2014

December 21, 2014

Posted by **Susie** on Monday, February 21, 2011 at 12:58pm.

- calculus -
**MathMate**, Monday, February 21, 2011 at 1:37pmDifferentiate both sides with respect to t:

dy/dt = d(sqrt(1+x^3))/dx * dx/dt

=(3x²/(2sqrt(1+x³)))*dx/dt

So given x=2,y=3 and dy/dt=3 cm/s

substitute in formula above to solve for dx/dt.

I get dx/dt=2.

**Answer this Question**

**Related Questions**

calculus - A particle moves along the curve y=square sqrt 1+x^3. As it reaches ...

calculus - I need help setting up this problem: A particle moves along the curve...

math - a particle moves along the curve y= sqrt 1+x cubed. As it reaches the ...

Calculus - A particle moves along the curve y = sqr(1+x^3). As it reaches the ...

Calculus - A particle moves along the curve y = sqr(1+x^3). As it reaches the ...

college calculus - 1) each side of a square is increasing at a rate of 6cm/s. At...

calculus - A particle is moving along the curve below. y = sqrt(x) As the ...

Calculus HELP - A particle is moving along the curve y=5 sqrt (2x+6). As the ...

Calculus 1 - A particle is moving along the curve y= 4 \sqrt{3 x + 1}. As the ...

calculus (related rates) - A particle moves in the plane along the curve y=xln(x...