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Posted by Anonymous on Monday, February 21, 2011 at 3:19am.
equation of the tangent line to the curve y = 2x²-x+10 at the point (-1,13)
dy/dx = slope = m = 4x-1 m = 4(-1) - 1 = -5 so y = -5 x + b find b 13 = -5(-1) + b b = 8 so y = -5 x + 8
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